JTP _ 12345 를 12,345 로

# -*- coding: cp949 -*-
# commanumber.py
import string

def comma_number(number):
        if number[0] in ['+', '-']:
                sign_mark, number = number[:1], number[1:]
        else:
                sign_mark = ''
        try:
                tmp = string.split(number, '.')
                num = tmp[0]; decimal = '.' + tmp[1]
        except:
                num = number; decimal = ''
        head_num = len(num) % 3
        result = ''
        # ~~~~~
        for pos in range(len(num)):
                if pos == head_num and head_num:
                        result = result + ','
                elif (pos - head_num) % 3 == 0 and pos:
                        result = result + ','
                result = result + num[pos]
        # ~~~~~
        return sign_mark + result + decimal

print comma_number(" 12345678.345678")^m<="" p="">



# AL GO RI SM  알고리즘
# 1. 부호가 있나 검사
# 2. 소숫점(.) 이 있으면 기준잡고 앞부분만  head_num 에 담음

"""
질문:
        ~~~~~ 부터 ~~~~~ 까지 소스코드에서,
        소스코드 해석.
        코드가 이해가 안됨.
"""

# -*- coding: cp949 -*-
# commanumber.py
import string

def comma_number(number):
        if number[0] in ['+', '-']:
                sign_mark, number = number[:1], number[1:]
        else:
                sign_mark = ''
        try:
                tmp = string.split(number, '.')
                num = tmp[0]; decimal = '.' + tmp[1]
        except:
                num = number; decimal = ''
        head_num = len(num) % 3
        result = ''
        # ~~~~~
        for pos in range(len(num)):
                if pos == head_num and head_num:
                        result = result + ','
                elif (pos - head_num) % 3 == 0 and pos:
                        result = result + ','
                result = result + num[pos]
        # ~~~~~
        return sign_mark + result + decimal

print comma_number(" 12345678.345678")